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n^2+84n=2
We move all terms to the left:
n^2+84n-(2)=0
a = 1; b = 84; c = -2;
Δ = b2-4ac
Δ = 842-4·1·(-2)
Δ = 7064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7064}=\sqrt{4*1766}=\sqrt{4}*\sqrt{1766}=2\sqrt{1766}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-2\sqrt{1766}}{2*1}=\frac{-84-2\sqrt{1766}}{2} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+2\sqrt{1766}}{2*1}=\frac{-84+2\sqrt{1766}}{2} $
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